A particle of mass 0.390 g carries a charge of 2.50 times 10-8 C. The particle i

Question

A particle of mass 0.390 g carries a charge of 2.50 times 10-8 C. The particle is given an initial horizontal velocity that is due west and has a magnitude 4.00 times 104 m/s. What are the magnitude and direction of the mini mu m magnetic field that will keep the particle moving in the earth's gravitational field in the same horizontal, westward direction? Magnitude

Explanation / Answer

mg = q v B => B = mg/qv = 0.39e-3*9.8/(2.5e-8*4e4) = 3.82 T ------------------------------------------------------------------------------------------------------------------------------------------------------------------------ direction: southward

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