A particle of mass 0.350 kg is attached tothe 100 cm mark of a meter stick of ma

Question

A particle of mass 0.350 kg is attached tothe 100 cm mark of a meter stick of mass 0.125 kg. The meter stick rotates on a horizontal,frictionless table with an angular speed of 2.00 rad/s. (a) Calculate the angular momentum of thesystem when the stick is pivoted about an axis perpendicular to thetable through the 40.0 cm mark.
1....................kg·m2/s

(b) What is the angular momentum when the stick is pivoted about anaxis perpendicular to the table through the 0 cm mark?
2kg·m2/s (a) Calculate the angular momentum of thesystem when the stick is pivoted about an axis perpendicular to thetable through the 40.0 cm mark.
1....................kg·m2/s

(b) What is the angular momentum when the stick is pivoted about anaxis perpendicular to the table through the 0 cm mark?
2kg·m2/s

Explanation / Answer

        Given that the massof particle is m = 0.350 kg         mass of stickis M = 0.125 kg         Length ofstick is L = 1 m         The angularvelocity of stick is = 2.00 rad/s ------------------------------------------------------------    (b) the angular momentum when the stick ispivoted about an axis perpendicular to the table through the 0 cmmark                L = I0                    =(Istick + I particle)                    =( ML2/3 +m*L2)                    =---------kg.m2/s                       (a) the angular momentum of the system whenthe stick is pivoted about an axis perpendicular to the tablethrough the         40.0 cmmark                                 I = Io + m*(0.04m)2                Thenthe angular momentum L = I                                                               =----------  kg.m2/s                                                    

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