A wheel of radius 0.540 m starts from rest and accelerates uniformly to an angul

Question

A wheel of radius 0.540 m starts from rest and accelerates uniformly to an angular speed of 17.0 rad/s in 3.00 s.

A wheel of radius 0.540 m starts from rest and accelerates uniformly to an angular speed of 17.0 rad/s in 3.00 s. Calculate the final linear speed of a point on the rim of the wheel. In other words, relate the velocity v to the angular velocity ? Calculate the angular acceleration of the wheel. Calculate the linear (tangential) acceleration of a point on the rim of the wheel. In other words, relate the acceleration a to the angular acceleration ? Calculate the angular displacement of the wheel. NOTE: The angular displacement is ?? in radians. You must specify "rad" as the unit.

Explanation / Answer

a) v = r*w = 0.54*17 = 9.18 m/s

b) alfa = (w2-w1)/t = (17-0)/3 = 5.67 rad/s^2

c) a_tan = r*alfa = 0.54*5.67 = 3.06 m/s^2

d)

theta = w1*t + 0.5*alfa*t^2

theta = 0 + 0.5*5.67*3^3 = 25.515 radians

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