A wheel has a constant angular acceleration of 2.9 rad/s 2 . During a certain 7.

Question

A wheel has a constant angular acceleration of 2.9 rad/s2. During a certain 7.0 s interval, it turns through an angle of 120 rad. Assuming that the wheel started from rest, how long had it been in motion before the start of the 7.0 s interval?

The angular position of a point on the rim of a rotating wheel is given by = 7.72t - 6.94t2 + 3.20t3, where is in radians and t is in seconds. What are the angular velocities at (a) t = 3.09 s and (b) t = 8.44 s? (c) What is the average angular acceleration for the time interval that begins at t = 3.09 s and ends at t = 8.44 s? What are the instantaneous angular accelerations at (d) the beginning and (e) the end of this time interval?

Explanation / Answer

The angular displacement of the particle in given interval of time is:

   =   1* t   +   (1/2) * *t2

120=1* 7  +   (1/2) * 2.9 *72

1=7.0rad/s

Now,

  1   =   0+ * T

Since the wheel is starting from rest

  1   =   0+ * T

  T=1 / =7.0/2.9=2.4 s

***Please post other question separately***

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