A block of mass 0.74 kg is suspended by a string which is wrapped so that it is

Question

A block of mass 0.74 kg is suspended by a string which is wrapped so that it is at a radius of 0.062 m from the center of a pulley. The moment of inertia of the pulley is 5.50

A block of mass 0.74 kg is suspended by a string which is wrapped so that it is at a radius of 0.062 m from the center of a pulley. The moment of inertia of the pulley is 5.50times10-3 kg·m2. There is friction as the pulley turns. The block starts from rest, and its speed after it has traveled downwards a distance of D= 0.73 m, is 1.740 m/s. Calculate the amount of energy dissipated up to that point.

Explanation / Answer

F=ma

=0.74*9.8

=7.25 N

energy =mg?h

= 0.74*9.8*0.73

=5.2 watt

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