1) A fully charged parallel plate capacitor stores 2.0E-6 J of energy when the p

Question

1) A fully charged parallel plate capacitor stores 2.0E-6 J of energy when the plates are separated a distance of 5.0 micrometers. Assuming that the capacitor is disconnected from energy batteries, how much energy will the capacitor store if the distance between the plates is reduced to 3.0 micrometers? 2)The capacitor from the previous problem is now connected to a 100 V battery. The separation between the capacitor plates remains 3 micrometers. If the area of the plates is 2 cm^2, what is the change in the amount of charge on the plates after they are connected to the battery.

Explanation / Answer

since, the battery is disconnected... the charge remains constant, energy and capacitance are inversaly proportional [E =Q^2/ 2C] capacitance is inversaly proportional to distance. so energy and distance are directly proportional. E1*d1 = E2*d2 E2 = 3.33 * 10^-6 J 2) capacitance = (epsilon) * A/d = 5.9*10^-10 F Q = VC = 590 micro-C

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.