A waitress in a diner slides a ketchup bottle with mass 0.2 [kg] along a smooth

Question

A waitress in a diner slides a ketchup bottle with
mass 0.2 [kg] along a smooth level lunch counter.
As it slides, it slows down because of the horizontal
resistive friction force exerted on it by the countertop.
We are told that the bottle leaves her hand with an
initial velocity of 2.8 [m/s], and comes to rest after
sliding a distance of 1 [m].
From this information, we can easily calculate the
magnitude of the bottle's acceleration to be 3.9 [m/s^2]

Calculate the coefficient of kinetic friction between the bottle and counter-top.

Explanation / Answer

friction coefficient=k=friction force/weight=3.9*0.2/(3.9*9.8)=0.0204

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