A skier starts from rest at the top of a frictionless incline of height 20.0 m,
ID: 2190168 • Letter: A
Question
A skier starts from rest at the top of a frictionless incline of height 20.0 m, as shown in the figure. At the bottom of the incline, the skier encounters a horizontal surface where the coefficient of kinetic friction between skis and snow is 0.201. Neglect air resistance.
Use the values from PRACTICE IT to help you work this exercise. Find the horizontal distance the skier travels before coming to rest if the incline also has a coefficient of kinetic friction equal to 0.201. Assume that ? = 20.0
Explanation / Answer
(Vb)= square root (2)(9.80m/s^2)(20.0m)=19.79 m/s (Vb) ^2 = 391.64. If there is friction the square of the velocity is reduced by a factor {1- ? / tan ?} = 1- 0.201/ tan 20 = 0.448 Vb^2 = 0.448x391.64 =175.45 the horizontal distance traveled = Vb^2 / [ 2 *0.201*9.8] = 44.54 m .
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