A skier is pulled by a tow rope up a frictionless ski slope that makes an angle

Question

A skier is pulled by a tow rope up a frictionless ski slope that makes an angle of 13 degree with the horizontal. The rope moves parallel to the slope with a constant speed of 0.61 m/s. The force of the rope does 810 J of work on the skier as the skier moves a distance of 7.7 m up the incline. (a) If the rope moved with a constant speed of 2.3 m/s, how much work would the force of the rope do on the skier as the skier moved a distance of 7.7 m up the Incline? At what rate is the force of the rope doing work on the skier when the rope moves with a speed of (b) 0.61 m/s and (c) 2.3 m/s?

Explanation / Answer

since constant speed is here so change in kinetic energy = 0

dKE = 0

W = -Wg

Wg is the same in both cases

Wg = 810 J

part b )

P = W/t

t = distance/speed = 7.7/0.61

P = 64.17 W

part c )

speed = 2.3 m/s

t = 7.7/2.3

P = 241.95 W

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