Two forces, F1 and F2, act at a point F1 has a magnitude of 8.00 and is directed

Question

Two forces, F1 and F2, act at a point F1 has a magnitude of 8.00 and is directed at an angle of = 57.0 above the negative x axis in the second quadrant. F2 has a magnitude of 5.20 and is directed at an angle of = 52.1 below the negative x axis in the third quadrant.

1. What is the magnitude of the resultant force? EXPRESS in N
2. What is the angle that the resultant force forms with the negative x axis? In this problem, assume that positive angles are measured clockwise from the negative axis.
Express your answer in degrees.

Explanation / Answer

F1x=-8 cos 57 F1y=8 sin 57 F2x=-5.2 cos 52.1 f2y=-5.2 sin 52.1 so Fx=F1x+F2x=-7.55 Fy=F1y+F2y=2.606 a)so F=sqrt(Fx^2+Fy^2)=8.00 b)arctan(Fy/|Fx|)=19.0 degree

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.