Two cars are driving along Robinson Street during an ice storm when they hit a p

Question

Two cars are driving along Robinson Street during an ice storm when they hit a patch of ice. The car in front is traveling at a speed of 8.5 m/s when it starts sliding and the car in back is traveling at a speed of 16.0 when it starts sliding. The mass of the front car is larger than the mass of the back car: Mfront = 2 Mback.

When the back car hits the front and the bumpers lock, how fast will the two cars be moving?

Give you answer to three digits in m/s, but do not include the units in your answer.

Explanation / Answer

Apply Law of Conservation of Momentum (M + 2M)*V = 2M*8.5 + M*16 V = 11 m/sec

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