Two capacitors, C1 = 4.01 F and C2 = 13.4 F, are connected in parallel, and the

Question

Two capacitors, C1 = 4.01 F and C2 = 13.4 F, are connected in parallel, and the resulting combination is connected to a 9.00-V battery.

(a) Find the equivalent capacitance of the combination. 17.41

(b) Find the potential difference across each capacitor. V1 = 9V V2 = 9V

(c) Find the charge stored on each capacitor. Q1 = 36.9 Incorrect. What is the relationship between the charge on a capacitor and the potential difference across that capacitor? Q2 = 120.6

It keeps telling me that my Q1 is wrong and asking me that question, but I don't understand why its wrong.

Explanation / Answer

A) For parallel capacitors, the equivalent capacitance of the combination is the sum of the individual capacitors, so C=C1+C2=4.01+13.4 = 17.45 uF.
B)The potential difference across each capacitor will be 9.00V. Since they are in parallel, the voltage drop across each must be the same and will equal the battery voltage.

C)

Q=CV, so Q1=4.01uF*9.00V=36.09uC.

                  Q2=13uF*9.00V=117uC.

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