Two capacitors, C1= 23.0 uF and C2= 32.0 uF, are connected in series, and a 3.0-

Question

Two capacitors, C1= 23.0 uF and C2= 32.0 uF, are connected in series, and a 3.0-V battery is connected across the two capacitors. a.) Find the equivalent capacitance b.) Find the energy stored in this equivalent capacitance c.) Find the energy stored in each individual capacitor ( capacitor1 and capacitor 2) e.) Will this equality always be true, or does it depend on the number of capacitors and their capacitances? f.) If the same capacitors were connected in parallel, what potential difference would be required across them so that the combination stores the same energy as in part a? g.) Which capacitor stores more energy in this situation, C1 or C2?

Explanation / Answer

the net capacitance in series =c1 *c2/ (c1+c2) = 13.38 uF Energy = 0.5*C*V^2 = 6.021 *10^-5 J q= V*C =4.014 *10^-5 C charge stored in each capacitor in series will be same Energy = 0.5 *q^2 /C energy in C1 =3.5* 10^-5 J energy in C1 =2.517* 10^-5 J equaliy is not always true. if they were in parallel net capacitance= 55uF v^2=2* E/c= 2.189 V potential difference across both capacitor issame so the oone having more capacitance will store more energy in this case 32uF

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