The drawing shows a collision between two pucks on an air-hockey table. Puck A h

Question

The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.029 kg and is moving along the x axis with a velocity of +5.5 m/s. It makes a collision with puck B, which has a mass of 0.064 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawing.Directional final velocity of puck a is 65degrees, this puck goes north east. Directional final velocity of puck b is 37 degrees this puck goes south east.

Explanation / Answer

If you finish the question I can answer it easily. What are the angles "shown in the drawing"? Are the final velocities what's wanted? Meanwhile I'll assume it's the same as the other puck question you posted. GIVENS masses m1, m2 = .029 .062 pre-collision velocities v1i, v2i = 5.5 0 post-collision angles T1f, T2f = 65 -37 deg SETUP P = m1v1i = .121 RESULTS post-collision velocities v1f, v2f: v1f = P / ((1/tan(T1f) - 1/tan(T2f))*m1*sin(T1f)) = 3.38392960822387 m/s v2f = P / ((1/tan(T2f) - 1/tan(T1f))*m2*sin(T2f)) = 1.80827716609214 m/s

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