The drawing (not to scale) shows the way in which the pressure and volume change

Question

The drawing (not to scale) shows the way in which the pressure and volume change for an ideal gas that is used as the working substance in a Carnot engine. The gas begins at point a (pressure = Pa, volume = Va) and expands isothermally at temperature TH=358 K until point b (pressure = Pb, volume Vb) is reached. During this expansion, the input heat of magnitude |QH| enters the gas from the hot resevoir of the engine. Then, from point b to point c (pressure = Pc, volume = Vc), the gas expands adiabatically. Next, the gas is compressed isothermally at temperature Tc=329 K from point c to point d (pressure = Pd, volume = Vd). During this compression, heat of magnitude |QC| is rejected to the cold resevoir of the engine. Finally, the gas is compressed adiabatically from point d to point a , where the gas is back in its initial state. The overall process a to b to c to d is called a Carnot cycle. Find |QC|/|QH|.

Can you help me find |QC|/|QH|?

Explanation / Answer

1 - Qc/Qh = efficiency = 1- Tc/Th = 1 - 329/358

1 - Qc/Qh = 0.081

Qc/Qh = 0.919

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