Two plastic spheres The figure shows two thin plastic spherical shells (shown in

Question

Two plastic spheres The figure shows two thin plastic spherical shells (shown in cross section) that are uniformly charged. The center of the larger sphere is at < 0, 0, 0 >; it has a radius of 12 cm and a uniform positive charge of 4 e-9 C. The center of the smaller sphere is at < 25, 0, 0 > cm; it has a radius of 3 cm and a uniform negative charge of -3 e-9 C. (a) What is the electric field at location A (6 cm to the right of the center of the large sphere)? Neglect the small contribution of the polarized molecules in the plastic, because the shells are very thin and don't contain much matter. <_ , _ , _> N/C (b) What is the electric field at location B (15 cm above the center of the small sphere)? Again, neglect the small contribution of the polarized molecules in the plastic, because the shells are very thin and don't contain much matter. <_ , _ , _> N/C (c) What is the force on an electron placed at location B? <_ , _ , _> N please explain how you get the answer as well. with equations used. thanks

Explanation / Answer

Assume that the fields from the two spheres are acting as though they are point charges at their centers. Calculate the two electric fields using the formula you used in (a) and superimpose (add) them. (0) 4 * p * e0 = 4 * 3.14 * 8.85 e-12 = 1.11e-10 (1) El (electric field from large sphere) = Ql / (1.11e-10 * d^2) = 5e-9 / (1.11e-10 * (0.25^2 + 0.15^2)) = 530.C (2) Es (electric field from small sphere) = Qs / (1.11e-10 * d^2) = -2e-9 / (1.11e-10 * (0.15^2)) = -801C (3) Enet = El + Es = 530.C - 801C = -271C (c) The force on the electron at B is given by: (4) F = qe * Enet = (-1.60e-19) * (-271) = 4.34e-17N

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