Two plane mirrors stand facing each other, 2.83 m apart, and a woman stands betw
ID: 1516469 • Letter: T
Question
Two plane mirrors stand facing each other, 2.83 m apart, and a woman stands between them. The woman faces one of the mirrors from a distance of 1.20 m and holds her left arm out to the side of her body with the palm of her left hand facing the closer mirror.
(a) What is the apparent position of the closest image of her left hand, measured perpendicularly from the surface of the mirror in front of her?
______m behind the nearer mirror
(b) What is the position of the next image?
m behind the nearer mirror
(c) What is the position of the third closest image?
m behind the nearer mirror
Explanation / Answer
dtot= 2.83, d1=1.20, d2=1.63
d2 = dtot - d1
= 2.83 - 1.20 = 1.63
a) =d1
d1 = 1.20 m behind the nearer mirror
b ) = d1+2(d2)
= 1.20 + 2*(1.63)
= 4.46 m behind the nearer mirror
c) = 2(d1+d2)+d1
= 2(1.20+1.63)+1.20
= 6.86 m behind the nearer mirror
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