Two perpendicular wire carrying equal currents of along +x and +y at the origin,

Question

Two perpendicular wire carrying equal currents of along +x and +y at the origin, in which of the following quadrants of the coordinate system could you find a point at which the net magnetic field is to zero/a) first and third b) second and forth c) first and second d) all quadrants e) none of the quadrants What is the answer to question 35, if the currents are along and y? a) first and third b) second and forth c) first and second d) all quadrants e) none of the quadrants Which one of the resistors in the following circuit carries the largest current? a) the 3 Ohm b) the 6 Ohm c) the 8 Ohm d) same for all e) no way to say What is the current in the 6 Ohm resistor of the circuit of the previous question? a) 4A b) 2 A c) 1.5 A d) 1 A e) none of these The electric current in which one of the resistors in the following figure is the largest? a) the 3 Ohm resistor b) the 4 Ohm resistor c) the 2 Ohm resistor d) same for all As an object gets closer to a converging lens its image a) gets larger b) gets smaller c) remains unchanged d) first gets larger and then gets smaller e) first gets smaller and then gets larger As an object gets closer to a diverging lens its image a) gets larger b) gets smaller c) remains unchanged d) first gets larger and then gets smaller e) first gets smaller and then gets larger In which of the following positions of the object 'O' is its image formed by a converging lens the object? a) O

Explanation / Answer

35. let + be out of page magnetic field and - be into the page magnetic field
then magnetic field in 4 quadrants due to wire with current in +x directgion from right hand rule = (+,+,-,-)
then magnetic field in 4 quadrants due to wire with current in +y directgion from right hand rule = (-,+,+,-)
so point with 0 field would exisst where fields cancel out so quadrant 1 and 3
a) first andf third quadrant
36. then magnetic field in 4 quadrants due to wire with current in -x directgion from right hand rule = (-,-,+,+)
then magnetic field in 4 quadrants due to wire with current in +y directgion from right hand rule = (-,+,+,-)
so point with 0 field would exisst where fields cancel out so quadrant 2 and 4
b) second andf fourth quadrant
37. all three are in parallel, least resistance = maximum current
a) 3 ohm,
38. V = IR ( ohms law)
12 = i*6
i = 2 A
b) 2A

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