The mens world record for the shot put, 23.12 meters, was set by Randy Barnes of

Question

The mens world record for the shot put, 23.12 meters, was set by Randy Barnes of the United States on May 20, 1990. If the shot was launched from 6.00 ft above the ground at an initial angle of 42.0 degrees, what was its initial speed.

Please show all of your work using distance and velocity formulas if possible and explain your steps. thank you . The answer is not 13.85. This answer gives you a distance of 32.896 meters traveled not 23.12. Make sure to check you answers by plugging them back into the formulas and finding the distance traveled with that velocity.

Explanation / Answer

the usual drill is to divide the motion into horizontal (X) motion and vertical (Y) motion and these equations Vx= Vi cos? Vy= Vi sin? Vx= X/t Y= Vy*t + 1/2 g t^2 yeah, it gets tedious so I combined the equations into one that makes quicker work of most trajectory problems ?Y = X*tan? + ( (g*X^2) / 2(Vi*cos?)^2 ) if the projectile comes back to ground level, ?Y = 0 which simplifies things a lot otherwise higher is positive and lower is negative X is the downrange horizontal distance Vi is initial velocity ? is the launch angle in this problem ?Y= -6.00 ft = -1.83 m ?=42.0 deg X = 23.12 m ?Y = X*tan? + ( (g*X^2) / 2(Vi*cos?)^2 ) -1.83 = 23.12(0.900) + ( (-9.81*534.5) / (2(Vi^2)(0.5523)) -22.64 = (-5243.4) / (1.1046 Vi^2) Vi^2 = 209.67 Vi = 14.48 m/s or 14.5 m/s to 3 sf

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.