The force shown in the attached figure is the net eastward force acting on a bal

Question

The force shown in the attached figure is the net eastward force acting on a ball.  The force starts rising at t = 0.020 s, falls back to zero at t = 0.062 s, and reaches a maximum force of 55 N at the peak.  Determine with an error no bigger than 25% (high or low) the magnitude of the impulse (in N-s) delivered to the ball.  Hint: Do not use J = F?t. Look at the figure.  Find the area of a nearly equally sized triangle.

the picture has force on the left with the max being 55 then a parabola starting at .02 and ending at .062 with the max of 55.

Explanation / Answer

Where is fig???

Draw a vertical line from the peak (20 N) down to the x-axis (= time).

Calculate the area of each triangle, and add the areas:

If the graph is symmetrical: Area of each triangle = 20(0.025)/2 = 0.25 Newton-seconds

Impulse = 0.50 Newton-seconds.

If the force is not a linear function of time, you will need to sketch an equivalent triangle.

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