The force exerted by the wind on the sails of a sailboat is 100 N at 80º south f

Question

The force exerted by the wind on the sails of a sailboat is 100 N at 80º south from east while the water exerts a force of 220 N at 10º south from west. All angles are measured relative to the positive x axis. If the boat has a mass of 350 kg:

a) What are the magnitude and direction of its acceleration?
b) Assuming that the boat is at the coordinate origin at t = 0, what is its displacement in 4.0 seconds if the initial velocity was 1.0 m/s due north?

**A picture would help me A LOT in understanding this problem**

Explanation / Answer

Horizontal component of forces = Fh = 100*cos80 – 220*cos10 = -199.3 N

Vertical component of forces = Fv = -100*sin80 – 220*sin10 = -136.7 N

Magnitude = F = sqrt(Fh^2 + Fv^2) = 241.7 N

Angle = arctan(136.7/199.3) = 34.5 degree

Now acceleration = a = F/m = 241.7/350 = 0.7 m/s^2 at 34.5 degree

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