Hello, I need some assistance with successfully solving these physics problems.

Question

Hello, I need some assistance with successfully solving these physics problems. Help is much appreciate. Thank you so much in advance! I will award point as immediately as possible once I receive an acceptable answer. Have a nice day!

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A charged particle moving through a magnetic field at right angles to the field with a speed of 24.7 m / s experiences a magnetic force of 2.78 Times 10 - 4 N. Determine the magnetic force on 3n identical particle when it travels through the same magnetic field with a speed of 5.94 m / s at an angle of 21.2 degree relative to the magnetic field. As shown in the figure, two frictionless conducting rails (#1 and #2) are attached to a 20.0 degree incline such that the inside edges are 80.0 cm apart. A copper bar with a mass of 0.302 kg slides (without friction) at a constant speed down the conducting rails. If there is a vertical magnetic field of 0.0476 T in magnitude in the region of the incline, determine the magnitude of the current I that flows through the sliding copper bar. I = A What is the direction of the current in the sliding bar?

Explanation / Answer

1) F 1= B q v 1

B q = F1/v1 =

F2 = B*q*v2*sin*theta) = = F1*v2*sin21.2/v1 = 2.78*10^-4 * 5.94*sin21.2 / 24.7 = 24.176433e?6 N

2) B*i*L*= M*g*sin(theta)

I = 0.302*9.8*sin20 / (0.0476*0.8) = 26.58 A

from rail 2 to rail 1

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