A projectile is launched at an angle of 45.0 degrees above the horizontal with a

Question

                                       A projectile is launched at an angle of 45.0 degrees above the horizontal with an initial speed of 405 m/s and lands at the same level from which it was launched. The range is 125 meters. The time of flight is      seconds? (Hint: This may not happen on Earth!)

A projectile is launched at an angle of 56.6 degrees above the horizontal with an initial speed of 68.2 m/s. The horizontal component of its velocity is      m/s

A projectile is launched at an angle of 48.9 degrees above the horizontal and lands at the same level from which it was launched 2.63 seconds later. The magnitude of the initial velocity is      m/s

Explanation / Answer

1)maximum rage=125 m

so,

u^2/g=125

or 405^2/a=125

or a=1312.2 m/s^2

so time of flight=2usintheta/a

=2*405*0.707/1313.2

=0.4361 s

2)vx=68.2cos56.6

=37.54 m/s

3)let it be v.so,

2usintheta/g=t

or 2*v*0.753/9.8=2.63

or v=17.11 m/s

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