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Two long, parallel wires carry currents of I 1 = 3.28 A and I 2 = 4.55 A in the

ID: 2133489 • Letter: T

Question

Two long, parallel wires carry currents of I1 = 3.28 A and I2 = 4.55 A in the direction indicated in the figure below. (Choose the line running from wire 1 to wire 2 as the positive x-direction and the line running upward as the positive y-direction.)

magnitude     Two long, parallel wires carry currents of I1 = 3.28 A and I2 = 4.55 A in the direction indicated in the figure below. (Choose the line running from wire 1 to wire 2 as the positive x-direction and the line running upward as the positive y-direction.)

Explanation / Answer

b)
B2 = mue*I1/2*pi*d = 4.55*10^-6 T

B2x = B2 = 4.55*10^-6 T

B2y = 0

B1 = mue*I2/(2*pi*d*sqrt(2) ) = 3.22*10^-6 T

B1x = B1*cos(45) = 2.27*10^-6 T

B1y = -B1*sin(45) = -2.27*10^-6 T

Bnet,x = B1x+B2x = 6.82*10^-6 T

Bnet,y = B1y + B2y = -2.27*10^-6 T

angle between B1 and B2 is 45 degrees

Bnet = (B1^2+B2^2+2*B1*B2*cos(45)) = 7.195*10^-6 T


theta = tan^-1(Bnety/Bnetx) = 341.6 degrees with +x axsi in counter clockwise direction

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