6) According to quantum mechanics, the position (x) of a particle in a one dimen
ID: 2133268 • Letter: 6
Question
6) According to quantum mechanics, the position (x) of a particle in a one dimensional box with
dimensions - L/2 ? x ? L/2 (L constant) can be described by the following probability
distribution function p(x):
p(x) = Acos2[?x/L] for -L/2 ? x ? L/2, and 0 for all other x.
a) Find the normalization constant A in terms of L.
b) Find the mean, mode, and median position of the particle in the box.
c) Show that the variance (?^2) of x is given by:
?^2=((L/pi)^2)*((pi^2-6)/12)
d) What is the probability of finding the particle in the region: L/4 ? x ? L/2?
Explanation / Answer
PART (b)
Plot the "p(x) = Acos2[?x/L]"; for -L/2 ? x ? L/2
According to this diagram, we find:
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x_mode = 0
(x=0 is most probable point)
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x_median = 0
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