6) A block of mass 1.6 kg is attached to a horizontal spring that has a spring c

Question

6) A block of mass 1.6 kg is attached to a horizontal spring that has a spring constant k of 1 x 103 N/m. The spring is compressed 2.0 cm and is then released from rest on a frictionless surface.
a) Calculate the speed and elastic potential energy of the block as it passes through the equilibrium position x = 0. (Elastic potential energy means potential energy associated with a stretched or compressed spring.)
b) Calculate the speed and elastic potential energy of the block when it is in the position x = 1.1 cm.

Explanation / Answer

A. Due to compression Total P.E is converted into K.E

P.E = (0.5)Kx2

K.E = (0.5)mv2

P.E = K.E

x = 2cm

v = x Sqrt ( K /m )

= (0.02) Sqrt ( 1000 / 1.6 )

v = 0.5 m/s

P.E = (0.5)Kx2

= 0.2 J

B. x = 1.1cm

P.E = K.E

v = x Sqrt ( K /m )

= (0.011)Sqrt ( 1000 / 1.6 )

  v = 0.275m/s   

P.E = (0.5)Kx2

= 0.0605 J

Related Questions

Navigate

• Browse (All)
• Browse 6
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.