A 150kg mass is suspended by wires from two hooks and the lengths of the wires h

Question

A 150kg mass is suspended by wires from two hooks and the lengths of the wires have been adjusted so that they are 50 degree from horizontal. If the two hooks support the mass equally, calculate the vertical component of force Fv (vertical force) on the right hook. By using the result in part a calculate the horizontal component of force Fh (horizontal force). Determine the force exerted on the mass in the direction of the wire FR (force resultant force). If we move the hooks farther apart to reduce the angle from 50

Explanation / Answer

a) 2*Tsin50 = 150*9.8
T = 959.47 N
vertical component of force,

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