A 150N sled is pulled up a 28degree slope at constant speed bya 100N force that

Question

A 150N sled is pulled up a 28degree slope at constant speed bya 100N force that is parallel to the slope. What is the coeffecient of kinetic friction between the sledand the slope? The sled is then released when near the top of the hill. Whatis the acceleration of the sled as it slides down the hill? A 150N sled is pulled up a 28degree slope at constant speed bya 100N force that is parallel to the slope. What is the coeffecient of kinetic friction between the sledand the slope? The sled is then released when near the top of the hill. Whatis the acceleration of the sled as it slides down the hill?

Explanation / Answer

weight of sled W = 150 N angle = 28 degrees Applied force F = 100 N It moves with constant speed . So, frictional force = applied force         W cos = F from this   the coeffecient of kinetic frictionbetween the sled and the slope = F / ( W cos 28 )                                                                                                                   = 0.755      

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