A 150-g block is projected up a ramp with an initial speed of 8.1 m/s. The coeff

Question

A 150-g block is projected up a ramp with an initial speed of 8.1 m/s. The coefficient of kinetic friction between the ramp and the block is 0.23. (a) If the ramp is inclined 28

Explanation / Answer

Let the block travel L meter on the ramp, Than the vertical height gained (h) = Lsin25 = 0.42L meter The Friction force Ff = coefficient of kinetic friction x mgsin25 =>Ff = 0.23 x m x 9.8 x 0.42 = 0.95m Newton The work done by the friction force W = Ff x s = Ff x L = 0.95mL Jule ----------------(i) The initial KE = 1/2mv^2 = 1/2 x m x 7^2 = 24.5m Jule ------------------------------------(ii) The final PE = mgh = m x g x 0.42L = 4.12mL Jule ------------------------------------(iii… By PE = KE - W =>4.12mL = 24.5m - 0.95mL =>3.17L = 24.5 =>L = 24.5/3.17 = 7.73 m

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