Question Part Points Submissions Used A 84-kg man stands on a spring scale in an

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Question Part Points Submissions Used A 84-kg man stands on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.2 m/s in 0.94 s. The elevator travels with this constant speed for 5.0 s, undergoes a uniform negative acceleration for 1.5 s, and then comes to rest. What does the spring scale register in each of the following time intervals? (a) before the elevator starts to move
N

(b) during the first 0.94 s of the elevator's ascent
N

(c) while the elevator is traveling at constant speed
N

(d) during the elevator's negative acceleration
N
Question Part Points Submissions Used
Question Part Points Submissions Used
Question Part Points Submissions Used
Question Part Points Submissions Used
Question Part Points Submissions Used A 84-kg man stands on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.2 m/s in 0.94 s. The elevator travels with this constant speed for 5.0 s, undergoes a uniform negative acceleration for 1.5 s, and then comes to rest. What does the spring scale register in each of the following time intervals? (a) before the elevator starts to move
N

(b) during the first 0.94 s of the elevator's ascent
N

(c) while the elevator is traveling at constant speed
N

(d) during the elevator's negative acceleration
N A 84-kg man stands on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.2 m/s in 0.94 s. The elevator travels with this constant speed for 5.0 s, undergoes a uniform negative acceleration for 1.5 s, and then comes to rest. What does the spring scale register in each of the following time intervals? (a) before the elevator starts to move
N

(b) during the first 0.94 s of the elevator's ascent
N

(c) while the elevator is traveling at constant speed
N

(d) during the elevator's negative acceleration
N (a) before the elevator starts to move
N

(b) during the first 0.94 s of the elevator's ascent
N

(c) while the elevator is traveling at constant speed
N

(d) during the elevator's negative acceleration
N Question Part Points Submissions Used

Explanation / Answer

a1 = 1.2/0.94 = 1.28 m/s^2

a2 = -1.2/1.5 = -0.8 m/s

a) 84*9.8 = 823.2 N

b) 84*(9.8+1.28) = 930.72 N

c)84*9.8 = 823.2 N

d)84*(9.8-0.8) = 756 N

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