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ID: 2121624 • Letter: S
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(46%) Wed 9:45 PM Yara Fakhoury Chrome File Edit View History Bookmarks Window Help o O O LON-CAPA Eureka c An object weighs 96.1 N Buoyancy and Water Lev C https:// 2.lite msu.edu 58fo2dd743560c8185 b58f 11c9 19245bb016cabd2a8efbec3ec687f1... Q E RTF Yara Nidal Fakhoury (Student section: 731) Messages Courses Help Logout PHY 183B Summer 2013 rsonal n...Part 2 Main Menu Course Contents Evaluate Course Contents HW #8 (07/25 Th 11:59 PM) Eureka Notes Bookmark Communicate Print iTunes Store An object weighs 61.2 N in air. When it is suspended from a force scale and completely immersed in water the scale reads 15.9 N. Determine the density of the object. en Shot 3...9 PM Submit Answer Incorrect. Tries 2/12 Previous Tries When the object is immersed in oil, the force scale reads 39.8 N. Calculate the density of the oil en Shot 3...4 PM Submit Answer Tries 0/12 Preferences on what is marked as NEW Threaded View Chronological View Sorting/Filtering options Export? Mark NEW posts no longer new RTF dscap NEW Paul Daniel Heeder (heederpa:msu) Reply (Sat Jul 20 05:16:30 pm 2013 (EDT)) Any help on part 2? NEW Re Jessica Shea Goldsworthy (goldswo7:msu) Reply (Mon Jul 22 06:32:25 pm 2013 (EDT)) Use (p object)/(p oil) 3 (weight)/(weight-apparent weight in oil) Use what you solved for in part 1 for the density of the object and solve for the p oil RTF NEW Megan G White (whiteme9:msu) Reply (Tue Jul 23 01:53:57 pm 2013 (EDT)) eate Not sure how to do part 1. Any help?Explanation / Answer
PART(A)
(density of object)* volume*g=61.2N
(density of object)* volume*g -(density of water)* volume*g=15.9 N
density of object=61.2/(61.2-15.9)=1.351 gm/cm^3
PART(B)
(density of object)* volume*g=61.2N
(density of object)* volume*g -(density of oil)* volume*g=39.8 N
61.2-(density of oil)*61.2/1.351=39.8
(density of oil)=0.4724 gm/cm^3
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