An AM radio station broadcasts an electromagnetic wave with a frequency of 561 k

Question

An AM radio station broadcasts an electromagnetic wave with a frequency of 561 kHz, whereas an FM station broadcasts an electromagnetic wave with a frequency of 88.0 MHz. How many AM photons are needed to have a total energy equal to that of one FM photon?
An AM radio station broadcasts an electromagnetic wave with a frequency of 561 kHz, whereas an FM station broadcasts an electromagnetic wave with a frequency of 88.0 MHz. How many AM photons are needed to have a total energy equal to that of one FM photon?
An AM radio station broadcasts an electromagnetic wave with a frequency of 561 kHz, whereas an FM station broadcasts an electromagnetic wave with a frequency of 88.0 MHz. How many AM photons are needed to have a total energy equal to that of one FM photon?

Explanation / Answer

Energy = h(planck's constant) x frequency

so, to get the final answer we just have to divide the given two frequencies.

=> (88 x 10^6)/(561 x 10^3) = 156.86

so 157 AM photons are required to have the energy of a FM photon.

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