(a) Find the potential V on the x axis at x = 3.00 m and at x = 3.01 m. In this

Question

(a) Find the potential V on the x axis at x = 3.00 m and at x = 3.01 m. In this part, enter your answers to exactly 6 signfificant figures.

At x = 3.00 m:

kV   
Number of significant digits required = 6

At x = 3.01 m:

kV   
Number of significant digits required = 6

(b) Does the potential increase or decrease as x increases?

kV/m   
Number of significant digits required = 2

(c) Find the electric field at x = 3.00 m. In this part, enter your answer to exactly 2 significant figures.

kV/m to the right   
Number of significant digits required = 2

(d) Find the potential at the point x = 3.00 m, y = 0.01 m. In this part, enter your answer to exactly 4 significant figures.

kV   
Number of significant digits required = 4

and compare it with the potential, expressed to 4 significant figures, found for x = 3.00 m in (a).

GIve me a number answer please not equations.Please answer regard to significant figures and digits

Explanation / Answer

Part A)

V = kq/r

V = (8.99 X 10^9)(10.3 X 10^-6)/(3)

V = 30865.7 V

V = kq/r

V = (8.99 X 10^9)(10.3 X 10^-6)/(3.01)

V = 30763.1 V

Part B)

Potential decreases with distance

(30865.7 - 30763.1)/(.01) = 10 kV/m

Part C)

E = kq/r^2

E = (8.99 X 10^9)(10.3 X 10^-6)/(3^2)

E = 10 kV/m

This is in agreement with part B

Part D)

The distance r is found by the pythagorean theorem

d^2 = 3^2 + .01^2

d = 3 m

V = kq/r

V = (8.99 X 10^9)(10.3 X 10^-6)/(3)

V = 30865.7 V

This is in agreement with a

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