(a) Find the force P that must be applied to a piston of area 10.10 cm 2 to prod

Question

(a) Find the force P that must be applied to a piston of area 10.10 cm2 to produce sufficient fluid pressure to support a car weighing 11,151 N by means of a column of fluid of cross sectional area 280 cm2 as seen in the figure below.


(b) Find the increase in the car's gravitational potential energy when it is raised 1.00 m.


(c) How far must the smaller piston move in order for the larger one to move 1.00 m?


(d) Calculate the work done by P in moving the smaller piston.


Compare your answer with the answer to part b.

This answer has not been graded yet.

Explanation / Answer

in both the columns, pressure values are equal.

part a:

pressure on right side column=force/area

=11151/(280*10^(-4) m^2)=398250 N/m^2

hence if applied force is P on left column,

then P/(10.1*10^(-4) m^2)=398250

=>P=402.2325 N

part b:

increase in gravitational potential energy=weight*increase in height

=11151*1=11151 J

part c:

work done on the car to move it 1 m=increase in its potential energy=11151 J

hence the force P has to provide the same energy.

as work done=force*distance

==>11151=P*distance

==>distance=11151/P=11151/402.2325=27.72 m

part d:

work done by force P=force*distance=P*27.72

=11151 J

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