(a) Find the amplitude. m (b) Find the wavelength. m (c) Find the wave speed. m/
ID: 1676501 • Letter: #
Question
(a) Find the amplitude.m
(b) Find the wavelength.
m
(c) Find the wave speed.
m/s
(d) Find the period of the wave.
s
(e) Find the maximum speed of a particle in the string.
m/s
(f) Complete the equation describing the traveling wave, inwhich x and y are in metersand t is in seconds.
y(x, t) = sin( x + t + )
A sinusoidal transverse wave is traveling along a string in thenegative direction of an x axis. The figurebelow shows a plot of the displacement as a function of position attime t = 0. The x axis ismarked in increments of 5 cm andthe y axis is marked in incrementsof 5 cm. The string tensionis 3.1 N, and its linear densityis 31 g/m. (a) Find the amplitude. m (b) Find the wavelength. m (c) Find the wave speed. m/s (d) Find the period of the wave. s (e) Find the maximum speed of a particle in the string. m/s (f) Complete the equation describing the traveling wave, inwhich x and y are in metersand t is in seconds. y(x, t) = sin( x + t + )
Explanation / Answer
a) A = 5 * .05 =.25 m b) = 4 * .05 = .20 m c) v = (F / (m / L)) = (3.1 / .031) = 10 m /s d) f = v / T = 1 / f = / v =.2 / 10 =.02 sec e) y = A sin t variation of amplitude with time (dy / dt)max = A =2 f A = 2 * 50 * .25 = 78.5 m/s f) y = A sin (k x + v t) + signfor wave moving in negative direction (k = 2 /) y = A sin (2 x / + v t + )to include the phase At t = 0 .8 = sin sincethe amplitude is 80% of its maximum = 127 deg = 2.22rad Since the wave is traveling to the left, at t = 0 it haspassed its maximum amplitude and has dropped to .8 * ARelated Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.