(a) Find the force P that must be applied to a piston of area 10.60 cm 2 to prod

Question

(a) Find the force P that must be applied to a piston of area 10.60 cm2 to produce sufficient fluid pressure to support a car weighing 11,201 N by means of a column of fluid of cross sectional area 320 cm2 as seen in the figure below.


(b) Find the increase in the car's gravitational potential energy when it is raised 1.00 m.


(c) How far must the smaller piston move in order for the larger one to move 1.00 m?


(d) Calculate the work done by P in moving the smaller piston.


Compare your answer with the answer to part b.

This answer has not been graded yet.

Explanation / Answer

w =11201 N , A1 =10.60cm^2 , A2 =320 cm^2

From hydraulic lift concpet

Pressure is same on two areas

p =F/A

P/A1 = w/A2

P = (A1/A2)w = (10.60/320)(11201)

P = 371.03 N

(b) h =1m

U =mgh =wh = 11201*1 =11201 J

(c) A2/A1 =320/10.60 = 30.2

distance travelled by small piston d = 30.2*1

d= 30.2 m

d) Work done by P is W = P*d = 371.03*30.2

W = 11201 J

Work done P is equal to change in gravitational potentail energy of car

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