(a) Find the permittivity of polypropylene. 1 C 2 /(N ·m 2 ) (b) Find the maximu
ID: 1667077 • Letter: #
Question
(a) Find the permittivity of polypropylene.1 C2/(N ·m2)
(b) Find the maximum permissible voltage across the capacitor toavoid dielectric breakdown.
2 V
(c) When the voltage equals the value found in part (b), find thesurface-charge density on each plate and the induced surface-chargedensity on the surface of the dielectric. on each plate 3 C/m2 on dielectric 4 C/m2 on each plate 3 C/m2 on dielectric 4 C/m2 A capacitor has parallel plates of area 19 cm^2 separated by 2.2 mm. The space between the plates is filledwith polypropylene (see the tablebelow). (a) Find the permittivity of polypropylene. 1 C^2/(N .m^2) (b) Find the maximum permissible voltage across the capacitor toavoid dielectric breakdown. 2 V (c) When the voltage equals the value found in part (b), find thesurface-charge density on each plate and the induced surface-chargedensity on the surface of the dielectric. on each plate 3 C/m^2 on dielectric 4 C/m^2
Explanation / Answer
permittivity of polypropylene.=1.94*10-11 capacitance of thecapacitor=0A/d=7.6*10-12 Ed=V E=7*107 V=154000 VOLTS Q=1.17C plate=6.16*10-4 on the plates on dielectric 3.36*10-4
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