A single closed loop of wire is positioned in a uniform magnetic field (as shown

Question

A single closed loop of wire is positioned in a uniform magnetic field (as shown below). The magnitude of the magnetic field is increased from 0.5 T to 2.5 T during a time interval of 0.10 seconds (while the loop is still in the field). The width of the loop (x) is 0.080 m and the height (y) is 0.030 m.

a) What is the magnetic flux inside the wire loop before the magnetic field begins to change?

b) Calculate the induced emf in the wire while the magnetic field is changing.

c) On the drawing, indicate which direction the induced current flows in the wire loop.

d) Determine the magnitude of the electric current in the loop. Note: The resistance of the wire is 2%u03A9.

e) Once the field has stabilized, the wire loop is then pulled directly to the right, out of the magnetic field, at a constant speed of 1.5 m/s. Calculate the induced emf in the wire as the loop is pulled out of the magnetic field.

Explanation / Answer

1. flux = .5 * (.08*.03)=.0012

2. emf = -rate of change in flux = (.5-2.5)*.08*.03/.1 =-.048V

c)couter clock wise

d) I = .048/R

e)E = 2.5*.03*1.5 = .1125 V

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