The problem states: \"A 400N weight is supported by a 1.6 meter, uniform beam on
ID: 2110378 • Letter: T
Question
The problem states:
"A 400N weight is supported by a 1.6 meter, uniform beam on a
nautilus machine attached to a hinge. An athlete applies a vertical
force F, at the end of the beam as shown below. If the beam's mass
is 20kg and the system is in static equilibrium;
a) draw a free body diagram for the beam (please advise what to
draw & in what direction)
b) determine the applied force (F)
c) determine the x and y components of the reaction force at the
hinge (we use "Rx" and "Ry" components"
The attached diagram shows a beam of 1.6 meters that is hinged
on the left side. It is at a 40 degree angle up (being held upright
by a man seated on the right side) An upward Force is drawn in at
the right end of the beam above where the man is holding
it. There is a 400N weight hanging down from the beam
at 1.2 meters (from left side to right side)
***Please provide all steps/formulas used to provide a clear
explanation of how each answer is found. Thank
you!
Explanation / Answer
Given s=3.96(a) a=0.01, |Z(0.005)|=2.58 (check standard normal table)E=0.5So n=(Z*s/E)^2 = (2.58*3.96/0.5)^2=417.532Take n=418-----------------------------------------------------------------------(b) E=1So n=(Z*s/E)^2 = (2.58*3.96/1)^2=104.383Take n=105
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