A piece of insulated wire is shaped intotwo circles.The radius of the upper circ

Question

A piece of insulated wire is shaped intotwo circles.The radius of the upper circle is 5.00 cm and that of the lower circle is 9.00 cm. The wire has a uniform resistance per unit length of 3.00 /m. A uniform magnetic field is applied perpendicular to the plane of the two circles, in the direction shown. The magnetic field is increasing at a constant rate of 10.00 T/s. What is the magnitude of the induced current in the wire? _______________mA What is the direction of the induced current in the wire?

Explanation / Answer

flux = B*A

flux = B*pi(r1^2 - r2^2)

emf = -d(flux)/dt

emf = -dB/dt*pi(r2^2 - r1^2)

R = resistanceper unit length*(2*pi*r1 + 2*pi*r2)

i = emf/R

i = -dB/dt*pi(r2^2 - r1^2) / R

i = 66.67 mA

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