1. Answer:Assuming that sychronous machine is a sychronous condenser where the r

Question

1. Answer:Assuming that sychronous machine is a sychronous condenser where the real power P=0 refer to question below

In a synchronous generator, assume Rs = 0 and Xs = 1.2 pu. The terminal voltage Va = 1<0 pu. It is supplying 1 pu power. Calculate all the relevant quantities to draw the phasor diagrams presented in chapter 9 (Figure 9.13 in Electric Power Systems text) if the synchronous generator field-excitation is controlled such that the reactive power Q is as follows:

Q = 0 Supplying Q = 0.5 pu Absorbing Q = 0.5 pu

a)

(Q=0 =>Iaq=0 )

finalized_jax">3Va*Ia=1

=>(Ia =1/3 pu =0.33 p.u)

(=> Eaf = sqrt{1^2+(0.33*1.2)^2} =1.075 p.u)

(delta = tan^{-1}(0.33*1.2/1)=21.60 degrees)

b)

supplying Q = 0.5 p.u

(I_{a} is leading V_{a} by heta)

(3Va*Iaq = 0.5 => Iaq = 0.5/3 =1/6 pu)

(P=1 => Ia*cos heta= 1/3pu)

finalized_jax">Ia+=0.372+pu

( heta =tan^{-1}[(1/6)/(1/3)] =26.565 degrees)

=>(Eaf = Va+jIaXs =1<0+0.372*1.2<116.565= 0.894<26.5128)

(Eaf =0.894 pu)

(delta =26.5129 pu)

c)

absorbing Q=0.5 p.u

(I_{a} is lagging V_{a} by heta)

(P=1 => Ia*cos heta= 1/3pu)(3Va*Iaq = 0.5 => Iaq = 0.5/3 =1/6 pu)

( heta =tan^{-1}[(1/6)/(1/3)] =26.565 degrees)

(Ia =0.372 pu)

(Eaf = Va+jIaXs =1<0+0.372*1.2<63.435= 1.264<18.408)

(Eaf =1.246 pu)

(delta =18.408 degrees)

Explanation / Answer

can you please write down the whole question. It's difficult to read it thi way.

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