The force required to stretch a spring varies directly with the amount the sprin

Question

The force required to stretch a spring varies directly with the amount the spring is stretched. A spring stretches by 46 m when a 98 N weight is hung from it and the weight is at rest (at equilibrium). The 98 N weight is replaced by an unknown weight W so that the spring is stetched to a new equilibrium position, 22 m below the position if no weight were attached. The weight W is then displaced from equilibrium and released so that it oscillates.
Calculate the period of motion. The acceleration of gravity is 9.8 m/s^2.
Answer in units of N

Explanation / Answer

k=F/X=98/46
W=22*98/46==>M=22*98/46*9.8
T=2(M/K)=2(22/9.8)=9.41 sec

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