A mass spectrometer is used to separate two isotopes of uranium with masses m1 a

Question

A mass spectrometer is used to separate two isotopes of uranium with masses m1 and m2 where m2 > m1. The two types of uranium atom exit an ion source S with the same charge of +e and are accelerated through a potential difference V. The charged atoms then enter a constant, uniform magnetic field B as shown. If r1 -0.5049m and r2 -0.5081m, what is the value of the ratio m1/m2 ?

a) 0.9984

b) 0.9937

c) 0.9874

d) 0.9812

e) 0.9749

Need help in checking this problem and making sure I did everything right. I was pretty confused with this entire thing! Thanks!

Explanation / Answer

qvB = mv^2/ r 1/2 mv^2 = qV 2 qV / r = qvB 2V = rvB v1 / v2 = r2 / r1 = 1.00633 putting in first equation mv/r = constant m1 v1 / r1 = m2 v2 / r2 m1/m2 = 0.9874 c) 0.9874

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