11. Two resistors of values 6 and 12 a are con hooked in series with a 4 ? resis
ID: 2038796 • Letter: 1
Question
11. Two resistors of values 6 and 12 a are con hooked in series with a 4 ? resistor and a resistor? raliei. This combination in 12 ? are conne?ted in pa A) 0.75 A B) 0S A C)0SA D) 6667A E battery. What is the current in the B) 9.6A 12. Which of the following radiations has the greates A) Visible B) Radio C) Infrared D) Ultraviolet E) X-rays and a 4,F capacitor were wired in parallel, what would be the charge leaving the 4F 13. If a 21 V battery, a 10 F capacitor battery?- JC A) 300 C B) 1050 JC C) 12c D) 294 C E) 47.62 JC 14. ', c-24 aF. and L-2H Find the impedance ofthe circuit. For a RCL series circuit with f-60 ? R-400 h. A) 800g B) 7580 C) 166.7a D) 3840a E) 1600 ohm lbs. 15. Ifv-0.85 c and mo- 140 Ibs, then what is m A) 680 Ibs. B) 149 lbs. C) 136 lbs. D) 265.8 bs. E) 47.6 bs. What is the force between 4 uC and 3 JC charges 0.5 meter apart A) 24N B) 18N C) 0.432N D) 2N E) 0.3N 6. A 3 ? particle of mass 4 x 10', Kg and velocity of 300,000 m/s enters into a 5 Tesla perpendicular magnetic field. What is the force on the charge?N A) 3 B) 4.5 C) 30 D) 60 E) 15 7 18. A transformer with 1100 turns on the primary coil is used to decrease the voltage from 2000 V to 120 V for home use. How many turns should be in the secondary coil? A) 1760 tums B) 66 turns C) 137.5 tums D) 4.4 turns E) 3.636364 turns 19. If anglesod 40 when nacid 1, and necfrasted 1.6, find angletracod A) 20° B) 30° C) 40 D) 23.7 E) 38.567256 20. What is the equivalent capacitance between points a and b? ALl capacitors are i nieroFarad ) 2.00 of C) 1.67 ?r D) 0.60 ?Explanation / Answer
11)Ans is:
(A)0.75 A
Explanation:
6 and 12 will make
R' = 6 x 12/(6 + 12) = 4 Ohm
Req = 4 + 4 = 8 Ohm
V = IR => I = V/R = 6/8 = 0.75 A
Same current will pass through 4 and then divide to the parallel combination.
Hence, (A)0.75 A
12)(E)X ray
Explanation:
Gamma has the highest frequency in the electromagnetic specturm, but its not given, next comes X rays, which is there in the options
13)(D)294 uC
Explanation:
Ceq = 10 + 4 = 14 uF
Q = CV = 14 u F x 21 = 294 uC
(D)294 uC
14)758 Ohm
explanation:
We know that
Z = sqrt (R^2 + (Xl - Xc)^2)
Z = sqrt [400^2 + (2 x 3.14 x 60 x 2 - 1/(2 x 3.14 x 60 x 24 x 10^-6))^2] = 758 Ohm
(B)758 Ohm
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.