A particle of mass m begins at rest from x = +18 cm and oscillates about its equ

Question

A particle of mass m begins at rest from x = +18 cm and oscillates about its equilibrium position at x = 0 with a period of 2.3 s. write expressions for the following. (Enter your numerical values to two decimal places.) (a) the position x as a function of t x(n-I(018)-cos( (27) x(t) (b) the velocity vx as a function of t Vy(t)-1-0.486 sin(27) X m/s (c) the acceleration ax as a function of t -1.3 cos The position of the particle as a function of time is given by x = Acos(at + 8). Its velocity and acceleration functions can be found by taking successive time derivatives of the position function.

Explanation / Answer

W=2pi/T =2pi/2.3 =2.73 rad/sec

Vx =dX/dt =d(ACosWt)/dt

Vx=-WASIn(Wt)

Vx=-2.73*0.18SIn(2.73t)

Vx=-0.4917 Sin(2.73t) m/s

Vx(t) =-0.49 Sin(2.7t) m/s

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