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is part a right and help in part B please!! 8. A positively charged particle (q-

ID: 2035659 • Letter: I

Question


is part a right and help in part B please!!

8. A positively charged particle (q- 5.5 C)is moving with a speed () of 2.4 m/s, directly figure below (a) What is the magnitude and direction of the magnetic force exerted on the particle m) a wire having a current (5.0A) flowing to the right, as shown in d 02 (b) If the positively charged particle has a velocity that is perpendicular to a current -carrying wire, as shown in the figure below, what will be the magnitude and direction of magnetic force on the charged particle?

Explanation / Answer

(a) Yes it is correct.

(b) The magnitude remains the same.

However the direction of the force changes as the direction of velocity has changed.

By right palm rule, the direction of force here is to the right.