is perfomed a Single F 200 13331130 15 3437 229 1333 22416 ource of 738 713 6394

Question

is perfomed a Single F 200 13331130 15 3437 229 1333 22416 ource of 738 713 63942.44 Within Groups 1474 819 1S. The corect null hy pothesis to test for any difference among methods is A. H: All true mean reading speeds differ (so, efficacies of methods differ) from each other. B. Ho: All true mean reading speeds are same (oqual). C. Ho: Several of the true mean reading speeds differ from each other D. Ho: Mean reading speed for Group 3 is less than that for the other groups E. Ho: Not all true mean reading speeds are equal. 16. The critical value of the test statistic for the above ANOVA at the 5% level of significance is approximately A. 1.37 B. 1.62 C. 2.85 D. 3.22 E. 4.04

Explanation / Answer

(15)

In framing the null hypothesis for any study, we assume that the outcome we are expecting does not happen.

Here we want to test if there are any differences. So in the null hypothesis we will assume by saying that there are no differences.

So the correct null hypothesis is:

H0: All the true mean readings are same(equal).

(16)

Here we first calculate the two degrees of freedom.

We have a total of 45 observations and 3 group means.

So, n = 45 and k = 3

Now,

df1 = k-1 = 2

df2 = n-k = 42

So using these df values and significance level of 5%, we have:

critical test statistic value = critical F-value = 3.219 = 3.22

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