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is owLv2 | Online teaching × e chegg Study I Guided s x C cvg.cengagenow.com/ilrn/takeAssignment/takeCovalent Activity do?locator-assignment-take&takeAssignmentSessionLocator-assignment-take; : Apps : kober portal D 2004 Saturn L300 H: web chemucsbedu -Baltimore Classificat Acute Viral Hepatitis Hepatitis A Treatme Jaundice: MedlinePl Other bookmarks Time Remaining 1:30:35 UNIT TEST Use the References to access important values if needed for this question. 1 pt 1 pr 1 pt 1 pt 1 pt 1 pt 1 pr 1 pt 1 pt 1 pt 1 pt 1 pr 1 pt 1 pt 1 pt 1 pt A mixture of hydrogen and argon gases, at a total pressure of 724 mm Hg, contains 0.341 grams of hydrogen and 2.53 grams of argon. What is the partial pressure of each gas in the mixture? Question 5 Question 6 Question 7 Question 8 mm Hg Hi Ar mm Hg Submit Answer Try Another Version 1 item attempt remaining Question 11 Question 12 Question 13 Question 15 Question 16 Question 17 Question 18 Progress: 0/25 items Due Nov 2 at Previous Next 11:00 PM 8:53 PM 11/2/2017Explanation / Answer
first calculate moles of both the gases
moles of H2 = 0.341 / 2 = 0.1705
moles of Ar = 2.53 / 40 = 0.06325
total moles = 0.1705 + 0.06325 = 0.23375
mole fraction of H2 = 0.1705 / 0.23375 = 0.73
mole fraction of Ar = 0.06325 / 0.23375 = 0.27
total pressure = Ptotal = 724 mmHg
PH2 = mole fraction of H2 x Ptotal
PH2 = 0.73 x 724
PH2 = 528.52 mmHg
PAr = mole fraction of Ar x Ptotal
PAr = 0.27 x 724
PAr = 195.48 mmHg
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