A proton with a velocity of 450 m/s in the +x direction enters a magnetic field

Question

A proton with a velocity of 450 m/s in the +x direction enters a magnetic field of strength 95 mT that points in the +x direction. (Don't forget to draw the path.) Force Acceleration (10 Points) Two parallel wires are carrying current in the +x direction. Wire 1 is 5 cm long, and wire 2 is 20 cm long. The wires are 3 cm apart. On the diagram, draw the magnetic field that wire 2 produces near Wire 1. Calculate the force vector that Wire 1 feels due to this magnetic field. Note: I1-2 A, 12-4.5 A Wire I- 11 Wire 2 Force-

Explanation / Answer

1st question:

The magnetic force is given by"

F = qvBsin(th) where th is the angle between v and B

Here, th = 0, so sinth = 0. Thus

F = 0N

So the acceleration is also zero, a = 0 m/s2

The proton will move unaltered, i.e. in the +x direction.

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