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A proton traveling at 3.70 km/s suddenly enters a uniform magnetic field of 0.71

ID: 1594407 • Letter: A

Question

A proton traveling at 3.70 km/s suddenly enters a uniform magnetic field of 0.710 T , traveling at an angle of 55.0 ? with the field lines (see (Figure 1) ).

PART A: Find the direction of the force this magnetic field exerts on the proton. (choices)

- The force is directed into the page.

- The force is directed out of the page.

PART B: Find the magnitude of the force this magnetic field exerts on the proton. Express your answer in newtons to three significant figures.

PART C: If you can vary the direction of the proton's velocity, find the magnitude of the maximum force you could achieve. Express your answer in newtons to three significant figures.

PART D: If you can vary the direction of the proton's velocity, find the magnitude of the minimum force you could achieve. Express your answer in newtons to three significant figures.

PART E: How should the velocity be oriented to achieve the forces in Parts C and D. (choices)

- F is maximum when v?  is perpendicular to B? . F is minimum when v?  is either parallel or antiparallel to B?.

- F is maximum when v?  is parallel to B? . F is minimum when v?  is perpendicular to B?.

PART F: What would the answer to Part A be if the proton were replaced by an electron traveling in the same way as the proton? (choices)

- Force is directed into the page.

- Force is directed out of the page.

PART G: What would the answer to Part B be if the proton were replaced by an electron traveling in the same way as the proton? Express your answer in newtons to three significant figures.

- F is maximum when v?  is perpendicular to B? . F is minimum when v?  is perpendicular to F? .

Explanation / Answer


A) into the page


B) F = q*v*B*sin(55) = 1.6*10^-19*3.7*1000*0.71*sin(55) = 3.44*10^-16 N


C) Fmax = q*v*B = 1.6*10^-19*3.7*1000*0.71 = 4.2*10^-16 N

D) Fmin = 0 N

E) F is maximum when v is perpendicular to B . F is minimum when V is either parallel or antiparallel to B


F) out of the page

G) F = q*v*B*sin(55) = 1.6*10^-19*3.7*1000*0.71*sin(55) = 3.44*10^-16 N

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